When this switch is positioned at ON, the other end of the lamp gets connected to ground i.e. the negative terminal of the battery hence, the lamp gets illuminated.
In OFF position, the lamp remains disconnected from the ground. In DOOR position, the lamp gets connected to the ground via door switches (in parallel). When a door is opened, the corresponding door switch is closed.
Fig. 2 shows the proposed car interior light fader circuit, when any of the door is opened, its switch is closed hence, the base of T1 gets connected to ground and thus stop conducting. In this state, C1 gets charged rapidly via R3 and D1.
As soon as C1 is charged, the mosfet is fed with the gate voltage thru R4 and thus it starts conducting and consequently the lamp is illuminated. Now, when that door is closed, its switch gets open. The base of T1 gets disconnected from the ground and is held at a voltage delivered by the R1/R2 voltage divider.
This action switches on T1, and the voltage coming from R3 finds it way to ground thru emitter of T1. The switching on of T1 deprives C1 of its charging current and thus C1 starts discharging slowly thru R4 and R5. The gate voltage of T2 reduces as C1 discharges.
With this reduction in the gate voltage the intensity of the lamp is also reduced. Finally, when the gate voltage goes below the threshold voltage the lamp switches off. The values of R5 and C1 are responsible for the fading delay time of the lamp. Increasing the values will increase the time and vice versa.
T2 should be any suitable N-channel mosfet capable of handling at least 50V and 10A. The whole circuit can be built on compact sized general purpose board and enclosed in the room lamp cover.
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